Professor Layton and the Last Specter/Puzzles 126-156

Caution! This page contains all the hints and solutions for every puzzle from 126 to 156. Scroll carefully or you might spoil the answer of a puzzle for yourself. The solutions are hidden behind spoiler tags, so only take a peek if you're desperate.

Puzzle 149

 * Name: Marble Thirds
 * Trigger: Repeatedly tap shrubs
 * Location: Market East
 * Chapter: 4
 * Picarats: 30

Description: The diameter of the circle below is divided into three equal lengths, and those lengths are used to make the marble-like design that splits the circle into three different-colored sections.

The areas of sections I and III are equal, but what about the area of section II? Is it less than, greater than, or equal to the area of I?


 * Hint 1: Bear in mind the following three sizes of semicircle: The biggest semicircles in the diagram. The medium-sized semicircles, with a length two-thirds the circle's diameter. The smallest semicircles, with a length one-third the circle's diameter. Use these different-sized semicircles to help you solve the puzzle.
 * Hint 2: Think of the area of the smallest semicircle as one. The diameter of the medium semi-circle is twice that of the small semicircle, so its area will be four times as large. The big semicircle has a diameter three times as big as the small one, so the area will be nine times as large.
 * Hint 3: To figure out the area of sections I or III, use the semicircles as follows: Big - Medium + Small = . Replacing these with the areas we found in Hint 2 gives us: 9 - 4 + 1 = 6. This should help you figure out how to determine the area of section II.
 * Super Hint: If you've followed along with all of the previous hints, the rest is easy. The big semicircle has an area of nine. Since it's a semicircle, the area of the whole circle is twice that, or 18. From this, subtract the size of the areas of sections I and III, and you're left with the area of II. All right then. What is it?

Puzzle 151

 * Name: Coax the Kitty!
 * Trigger: Repeatedly tap the large window on Greppe's house
 * Location: Twisted Light
 * Chapter: 5
 * Picarats: 30

Description: A cat has gotten stuck and needs to be rescued. She won't come when called, so you will have to coax her out with some fish. She's so hungry, she will head toward any fish she spots in her direct line of sight and eat it before looking around for the next fish. Get the cat to the star using only seven fish.


 * Hint 1: It's easiest to work backward from the star to the cat. How many fish are needed near the star alone?
 * Hint 2: It takes quite a few fish to coax the cat around the last couple of bends. Working backward from the star, you'll need one fish on the star itself, one to its left, one on the square below that, and then one to the left.
 * Hint 3: After deducting the four fish you'll need to use near the star, you'll have only three fish left to work with. You need to make the cat travel quite far with each remaining fish. Maybe there's a good spot up and to the right of the cat.
 * Super Hint: Continuing from Hint 3, you'll have just two fish left. One needs to be placed to the far left of the fish described in Hint 3. After that, the place for the remaining fish should be obvious.