Tunnels & Trolls: Crusaders of Khazan

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Tunnels & Trolls: Crusaders of Khazan
Developer(s)StarCraft, Inc.
Publisher(s)New World Computing
Year released1990
System(s)DOS, NEC PC-8801, NEC PC-9801, Sharp X1, Sharp X68000, Fujitsu FM-7
Preceded byThe Black Sage
Followed byTunnels & Trolls Adventures
SeriesTunnels & Trolls
Genre(s)Role-playing game
ModesSingle player
LinksTunnels & Trolls: Crusaders of Khazan at PCGamingWikiTunnels & Trolls: Crusaders of Khazan ChannelSearchSearch

Tunnels & Trolls: Crusaders of Khazan is a role-playing video game based on the Tunnels & Trolls pen-and-paper role-playing game. It also includes small portions from the Tunnels & Trolls Solo Adventure books.

It was developed by Liz Danforth (Magic the Gathering), Jon Van Caneghem (Might and Magic), and the Japanese studio StarCraft, Inc.. The game was originally released in Japan for six different sytems, and the MS-DOS port was then re-translated in English. Unfortunately, said port is the one that features the most limited graphics and sound.

Gameplay[edit]

As the party members defeat enemies and earn expeerience points, the enemies become stronger and more numerous, to the point that the game may become unbeatable. This is somewhat realistic: as real life soldiers fight a war, they get more weary and fight with more difficulty. In Crusaders of Khazan, this mechanic is an invitation to complete the quest quickly (as real-life adventurers would do), and to refrain from leisure exploration.

Easymode cheat[edit]

There is a cheat to adjust the difficulty of combats. In fact, the level and number of enemies is strictly dependent on the average level of the party members. A dead party member is considered at level zero, therefore the average level of the party would get lowered.

A player may start the game with a party of four, let one character die, and play through the game carrying around a dead companion. For example, if your party members are all at lv. 8, the average party level will be 8 ([8+8+8+8]/4 = 8). If one party member dies, the average party level will become 6 ([8+8+8+0]/4 = 6).

Table of Contents

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