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Professor Layton and the Curious Village/Puzzles 26-50: Difference between revisions
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Professor Layton and the Curious Village/Puzzles 26-50 (edit)
Revision as of 02:36, 1 April 2008
, 1 April 2008puzzles 36-43
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==Puzzle 036== | ==Puzzle 036== | ||
:Name: | :Name: Too Many Mice | ||
:Trigger: | :Trigger: Tap on the Alley Cat (Layton's Puzzle) | ||
:Location: | :Location: Clock Tower | ||
:Chapter: | :Chapter: 3 | ||
:Picarats: | :Picarats: 30 | ||
'''Description''': | '''Description''': Mice are famous for their ability to multiply at breakneck speeds. The type of mouse we have here gives birth once a month, birthing 12 babies each time. Baby mice mature and can give birth two months after they are born. You picked up one of these darling baby mice at the pet shop and brought it home the day after it was born. In 10 months from now, how many mice will you have? | ||
*'''Hint 1''': | *'''Hint 1''': You may be thinking there's going to be a lot of bothersome calculation involved in solving this puzzle, but you don't need to do anything complicated to find the answer. Read the problem over carefully. | ||
*'''Hint 2''': | *'''Hint 2''': Do you remember how many mice you started with? Have you considered how many mice you can expect, given that number? | ||
*'''Hint 3''': | *'''Hint 3''': Ok, let me spell it out for you. You need your mouse to become pregnant before it will give birth. What does the mouse need in order to become pregnant? | ||
'''Answer''': | '''Answer''': 1 | ||
==Puzzle 037== | ==Puzzle 037== | ||
:Name: | :Name: Brother and Sister | ||
:Trigger: | :Trigger: Talk to Lucy | ||
:Location: | :Location: Clock Tower | ||
:Chapter: | :Chapter: 3 | ||
:Picarats: | :Picarats: 40 | ||
'''Description''': | '''Description''': A boy and his big sister are sitting around the kitchen table chatting. "You know Sis, if I took away two years from my age and gave them to you, you'd be twice my age, huh!" "Well, why don't you just give me one more on top of that? Then I'll be three times your age." So just how old is each sibling? | ||
*'''Hint 1''': | *'''Hint 1''': Let's see if we can't pare this puzzle down a bit. When you take two years away from the brother's age and add them to the big sister's, she becomes twice his age. Additionally, when you take three years away from the brother and give them to the sister, she becomes three times older than he is. | ||
*'''Hint 2''': | *'''Hint 2''': You could try and solve this with an algebraic equation, but that's no way to tackle a puzzle! Try to reason your way through this one. Move two years from the brother's age, and the difference in age becomes four years. Move three years, and the difference widens to six years. Four years makes the sister twice as old as the boy. Six years makes her three times as old. | ||
*'''Hint 3''': | *'''Hint 3''': The brother and sister were born in the same year. | ||
'''Answer''': | '''Answer''': The brother and sister are both 6. | ||
==Puzzle 038== | ==Puzzle 038== | ||
:Name: | :Name: Island Hopping | ||
:Trigger: | :Trigger: Talk to Zappone | ||
:Location: | :Location: Fork in the Road | ||
:Chapter: | :Chapter: 3 | ||
:Picarats: | :Picarats: 20 | ||
'''Description''': | '''Description''': Here is an overhead view of a cluster of tropical islands. As you travel from Start to Goal, your objective is to visit every island exactly one time. The island folk say this can be accomplished with the addition of a single straight bridge. The only other rule is that your bridge can't cross over any preexisting bridge. So, where should your bridge go? | ||
*'''Hint 1''': | *'''Hint 1''': You need to visit each island exactly one time, but that doesn't mean that you have to cross every bridge to do so. | ||
*'''Hint 2''': | *'''Hint 2''': Try setting out from the start point and just proceeding on your merry way. If you come across an island you simply can't get to, you may have just stumbled upon your answer. | ||
*'''Hint 3''': | *'''Hint 3''': Examine the are around the middle of the island cluster closely. | ||
'''Answer''': | '''Answer''': Draw a bridge from the middle island containing a house with a purple roof to the island with the gray lighthouse on the left part of the screen. Hit SUBMIT. | ||
==Puzzle 039== | ==Puzzle 039== | ||
:Name: | :Name: One-Line Puzzle 2 | ||
:Trigger: | :Trigger: Talk to Agnes | ||
:Location: | :Location: Fork in the Road | ||
:Chapter: | :Chapter: 3 | ||
:Picarats: | :Picarats: 30 | ||
'''Description''': | '''Description''': The idea of one-line puzzles is to put your pen to paper and draw a shape without lifting your pen from the pad or retracing any lines. You can, however, cross lines. Now that you're familiar with the concept, look at the four pictures below. One of them cannot be drawn with one line. Which one is it? | ||
*'''Hint 1''': | *'''Hint 1''': Each picture should be composed of lines that meet at different points. With these pictures, if you find a single line that runs out beyond the others, you know you have to start your drawing there. Try tracing the answer out yourself. | ||
*'''Hint 2''': | *'''Hint 2''': Some points may be the convergence point for several lines. You need to think hard about which line to take in and out of the point in order to make the sketches work. If you pen is entering a point formed by an even number of lines, you will always be able to leave the point via another line. | ||
*'''Hint 3''': | *'''Hint 3''': Using Hints One and Two, it's actually quite easy to draw these shapes out yourself. Make sure that you start drawing the shape form a point that touches an odd number of lines. Don't forget, one is also an odd number. | ||
'''Answer''': | '''Answer''': Circle the picture of the top hat in the upper right. Hit SUBMIT. | ||
==Puzzle 040== | ==Puzzle 040== | ||
:Name: | :Name: How Old Is Dad? | ||
:Trigger: | :Trigger: Talk to Archibald | ||
:Location: | :Location: Market | ||
:Chapter: | :Chapter: 3 | ||
:Picarats: | :Picarats: 30 | ||
'''Description''': | '''Description''': A father and son are chatting when the son poses this question: "Dad, I'm 22 now, but just how old are you?" The father replies, "You wanna know how old your old man is, eh? Hmm, well, I tell you what. I'm as old as your age, plus half of my age." How old is the father? | ||
*'''Hint 1''': | *'''Hint 1''': It sounds convoluted, but look again at what's being presented. "I'm as old as your age, plus half of my age." This means that if you take away half of the father's age, you'll have the age of the son. As you already know, the son is 22. | ||
*'''Hint 2''': | *'''Hint 2''': What the father is essentially saying here is that if you add half of his age to the son's age, you'll get the father's age. If that's the case, the son's age must be half of the father's age. | ||
*'''Hint 3''': | *'''Hint 3''': As started in the second hint, half of the father's age is equal to the son's age. To put it another way, the father's age is tow times that of his son. | ||
'''Answer''': | '''Answer''': 44 | ||
==Puzzle 041== | ==Puzzle 041== | ||
:Name: | :Name: Spare Change | ||
:Trigger: | :Trigger: Talk to Gerard | ||
:Location: | :Location: Northern Path | ||
:Chapter: | :Chapter: 3 | ||
:Picarats: | :Picarats: 10 | ||
'''Description''': | '''Description''': A rope and coins are arranged as shown below. As you pull the ends of the rope out to the left and right, the rope will draw taut and push the coins to either side. Assuming you only get to keep the coins that end up on the top half of the rope, how many coins will you have? | ||
*'''Hint 1''': | *'''Hint 1''': There's no special trick to this puzzle. You just need to be diligent and count up those coins. | ||
*'''Hint 2''': | *'''Hint 2''': Try tracing the rope with your stylus as you count up the coins. If you fill in the area that will travel upward when the rope is taut, you should be able to get an answer without too much work. | ||
*'''Hint 3''': | *'''Hint 3''': There are 32 coins tangled in the rope. When all is said and done, you even pull in a third of them. | ||
'''Answer''': | '''Answer''': 9 | ||
==Puzzle 042== | ==Puzzle 042== | ||
:Name: | :Name: The Camera and Case | ||
:Trigger: | :Trigger: Talk to Gerard | ||
:Location: | :Location: Northern Path | ||
:Chapter: | :Chapter: 3 | ||
:Picarats: | :Picarats: 50 | ||
'''Description''': | '''Description''': While walking through a market on vacation, you notice a small stand selling cameras. A camera-and-case set is selling for $310. The seller tells you that the camera costs $300 more than the case itself and that the case costs the price of the set minus the cost of the camera. You decide you'd rather wait on buying a camera and opt to just buy the case alone. You hand the seller a $100 bill and see his eyes light up. Think fast now! How much change should you be getting back? | ||
*'''Hint 1''': | *'''Hint 1''': This puzzle isn't math intensive, but there is a particularly tricky aspect to it that trips most people up. The camera and case cost a total of $310 but differ in price by $300. | ||
*'''Hint 2''': | *'''Hint 2''': Ok, if you assume the case costs X, then the camera must cost X plus $300. This means that the camera itself must cost more than $300. | ||
*'''Hint 3''': | *'''Hint 3''': The case and camera cost $310 together. The camera costs $300 more than the case. It may seem like the answer is $300 for the camera and $10 for the case, but if you do the math, you'll see that the difference in price is only $290. Have you noticed that already? | ||
'''Answer''': | '''Answer''': 95 | ||
==Puzzle 043== | ==Puzzle 043== | ||
:Name: | :Name: Three Umbrellas | ||
:Trigger: | :Trigger: Talk to Lucy | ||
:Location: | :Location: Clock Tower | ||
:Chapter: | :Chapter: 3 | ||
:Picarats: | :Picarats: 20 | ||
'''Description''': | '''Description''': Three identical-looking umbrellas are sitting upright in a stand. Assuming the owners don't check their umbrellas' labels, what percentage chance is there that only two people will walk off with their own umbrella? | ||
*'''Hint 1''': | *'''Hint 1''': Don't lose focus of what's being asked. Keep in mind that you aren't being asked the percentage likelihood of you grabbing your own umbrella form a group of three. | ||
*'''Hint 2''': | *'''Hint 2''': If two people have already successfully taken their own umbrellas, then who does the final umbrella belong to? | ||
*'''Hint 3''': | *'''Hint 3''': Three umbrellas sit in a bin. Two people come by and take their own umbrellas by chance, but the third person fails to do so... Hey, is that even possible? | ||
'''Answer''': | '''Answer''': 0 (Zero) | ||
==Puzzle 044== | ==Puzzle 044== | ||
