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→Explorer Free Job Change: added starting method and meso cost source
(→Explorer Free Job Change: added genesis weapon) |
(→Explorer Free Job Change: added starting method and meso cost source) |
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===Explorer Free Job Change=== | ===Explorer Free Job Change=== | ||
For explorer jobs, from '''Level 101 onwards''', it is possible to change job within the same job type '''once per day'''. However, it comes with a huge cost. | For explorer jobs, from '''Level 101 onwards''', it is possible to change job within the same job type '''once per day'''. However, it comes with a huge cost. It can be done by '''going to the 4th job advancement NPC of the same job type and indicate that you do not like your job'''. | ||
A job change is restricted to the same job type. | A job change is restricted to the same job type. | ||
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*Pirate: Captain/Corsair, Viper/Buccaneer, Cannon Shooter | *Pirate: Captain/Corsair, Viper/Buccaneer, Cannon Shooter | ||
It cost '''1 Free Job Advancement Coin or mesos''' for each job change. Free Job Advancement Coin can be obtained from coin shop events usually, and it is usually tradable within the account. For the meso payment, it '''increases with character level and every 2 times that the character changed job (this record does not reset)''', and it is calculated as such. | It cost '''1 Free Job Advancement Coin or mesos''' for each job change. Free Job Advancement Coin can be obtained from coin shop events usually, and it is usually tradable within the account. For the meso payment, it '''increases with character level and every 2 times that the character changed job (this record does not reset)''', and it is calculated as such. (Source: http://www.inven.co.kr/board/maple/2304/15954) | ||
*Level 101~105: <math>10,000,000 \times [log(10 + 10 \times floor(N/2))]^2</math> | *Level 101~105: <math>10,000,000 \times [log(10 + 10 \times floor(N/2))]^2</math> | ||
*Level 106 and above: <math>(10,000,000+50,000 \times (Level-105)^2) \times [log(10 + 10 \times floor(N/2))]^2</math> | *Level 106 and above: <math>(10,000,000+50,000 \times (Level-105)^2) \times [log(10 + 10 \times floor(N/2))]^2</math> | ||