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Professor Layton and the Diabolical Box/Puzzles 101-125 (edit)
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{{spoiler|title=Answer|[[File:PLatDB_Puzzle_110_Solution.png|right]] Trace the route according to the picture.}} | {{spoiler|title=Answer|[[File:PLatDB_Puzzle_110_Solution.png|right]] Trace the route according to the picture.}} | ||
==Puzzle 111== | |||
:Name: How Many Turns? | |||
:Trigger: Talk to Barton | |||
:Location: Hotel Lobby | |||
:Chapter: 5 | |||
:Picarats: 50 | |||
'''Description''': Chelmey sent his squad out to investigate an incident. Before leaving, he said this: "I want you to search the entire area shown on this map. Take any route you want, but report how many times you turned in the process. You're free to turn left or right, but U-turns are strictly forbidden!" The bobbies completed their shift and returned to report their turns. Judging by their reports, though, it seems at least one man wasn't telling the truth. Mark the liars with an X. | |||
*'''Hint 1''': If one of the bobbies had said he turned a total of 1,000 times during the course of his investigation, the inspector would have no reason to doubt the bobby was telling the truth. | |||
*'''Hint 2''': With U-turns forbidden, there's a certain logic you should be able to find in all this confusion. | |||
*'''Hint 3''': Leaving the station and turning an odd number of times, regardless of the number, will land you on a vertical street. Conversely, turn an even number of times after leaving the station, and you'll end up on a road that runs horizontally across the screen. | |||
{{spoiler|title=Answer|The policemen that had an odd number of turns (105 and 113) are liars.}} | |||
==Puzzle 112== | |||
:Name: Turn On the Light | |||
:Trigger: Talk to Duke | |||
:Location: Museum Gate | |||
:Chapter: 5 | |||
:Picarats: 40 | |||
'''Description''': The board shown on the left is wired to the underside so that holding contact points A and B together turns the light on. Now look at the picture on the right. This light has three contact points: A, B, and C. No matter whether you hold contact points A and B, B and C, or A and C together, the light stays on. In that case, how must the wires be connected on the underside of the board? Draw the solution that requires the fewest number of connections. The dotted red line indicates a known wire. | |||
*'''Hint 1''': "No matter whether you hold contact points A and B, B and C, or A and C together, the light stays on." This might make you think that the electricity has to run through all three of these connections, but at the same time, the positive and negative signals need to be isolated from each other, which makes things more difficult. Read the conditions you have to meet again as carefully as you can. | |||
*'''Hint 2''': You might be tempted to construct something resembling a proper wiring job, but that won't do the trick here. Be flexible in your thinking about what will get the job done! | |||
*'''Hint 3''': You only need to draw one wire! | |||
{{spoiler|title=Answer|Connect the lightbulb directly to the battery.}} | |||
==Puzzle 113== | |||
:Name: A Stack of Ice | |||
:Trigger: Talk to Hopper | |||
:Location: Northeast Path | |||
:Chapter: 5 | |||
:Picarats: 30 | |||
'''Description''': You've stacked three dice in a column. At the points where two dice touch, the faces that are touching add up to five. If one visible face of the bottom die is showing a one, what number must be on the top face of the top die? In case you were wondering, each die is identical, and all sets of opposing faces on each die add up to seven. | |||
*'''Hint 1''': At the two points where two dice touch, the sum of the two faces making contact equals five. If that's so, then each of these four faces must be a number between one and four. | |||
*'''Hint 2''': The options for the top face of the bottom die are limited. That face can only be two, three, or four. | |||
*'''Hint 3''': Assume for a minute that the top face of the bottom die is four. If so, then the bottom face of the middle die must be a one, which would make the top face of this second die a six. Now you've ruled out one possibility, as this can't be the answer. | |||
{{spoiler|title=Answer|The visible face on the top die shows a 6.}} | |||
==Puzzle 114== | |||
:Name: Fair Compensation | |||
:Trigger: Revealed after solving Photo 001 | |||
:Location: Hotel Room | |||
:Chapter: 6 | |||
:Picarats: 40 | |||
'''Description''': Three houses face a single common field. The heads of these three houses, A, B, and C, decide to work together to seed the field. Unfortunately C injures himself right before work starts, so A and B do all the work together. To seed the entire field, A works five days and B works four. Feeling guilty, C decides to pay A and B for doing his part of the job. To thank them, C pays them a total of nine coins, divided up according to how much work each person did. Can you figure out how many coins A and B received? | |||
*'''Hint 1''': It's tempting to think that the answer is to pay each man a coin for each day he worked, resulting in a total of five coins for A and four coins for B. But then that wouldn't be much of a puzzle, would it? Remember, the original agreement was that each man would do an equal share of the work. | |||
*'''Hint 2''': Simply put, A and B are getting paid for doing the work C was supposed to do. When considering your answer, don't factor in the days A and B were supposed to work according to the agreement. | |||
*'''Hint 3''': The coins should be distributed based on the number of days each person worked to cover the three days C was supposed to have worked. A did two days, B did one. | |||
{{spoiler|title=Answer|A receives 6 coins while B receives 3.}} | |||
==Puzzle 115== | |||
:Name: Tricky Digits | |||
:Trigger: Talk to Krantz | |||
:Location: Hotel Lobby | |||
:Chapter: 4 | |||
:Picarats: 40 | |||
'''Description''': Two cards sit on a table. Each has a different single-digit number written on it. When set side by side, they form a two digit number. Then, by flipping their order, you can make another two-digit number. Adding the total from these two two-digit numbers gives you one of the totals shown below. Which one is it? | |||
*'''Hint 1''': Once you see the pattern that runs through this puzzle, it's not very difficult to solve. | |||
*'''Hint 2''': 15+51=66 34+43=77 53+35=88 So is the pattern clear yet? | |||
*'''Hint 3''': Isn't it funny how adding a two-digit number to another two-digit number with reversed digits always gives you a sum that's a multiple of 11? | |||
{{spoiler|title=Answer|The total is 44. The two cards show 1 and 3.}} | |||
{{Footer Nav|game=Professor Layton and the Diabolical Box|prevpage=Puzzles 76-100|nextpage=Puzzles 126-138}} | {{Footer Nav|game=Professor Layton and the Diabolical Box|prevpage=Puzzles 76-100|nextpage=Puzzles 126-138}} | ||